Determine the final angular speed after an elapsed time of 2s. Initial angular velocity Wo -13.0 rad/s Angular acceleration a -5.0 rad/s^2
We can use the formula for angular motion:
Δω = ωf - ωi = a*t
Where:
Δω is the change in angular speed
ωf is the final angular velocity
ωi is the initial angular velocity
a is the angular acceleration
t is the elapsed time
Rearranging the formula, we get:
ωf = ωi + a*t
Plugging in the values:
ωf = -13.0 rad/s + (-5.0 rad/s^2 * 2s)
ωf = -13.0 rad/s - 10.0 rad/s
ωf = -23.0 rad/s
Therefore, the final angular speed after an elapsed time of 2s is -23.0 rad/s.