A ball is thrown into the air with an initial upward velocity of 60 ft/s. Its height (h) in feet after t seconds is given by the function h = –16t² + 60t + 6. What will the height be at t = 3 seconds? (1 point) Responses 35 feet 35 feet 40 feet 40 feet 42 feet 42 feet 45 feet 45 feet
To find the height at t = 3 seconds, we substitute t = 3 into the equation h = –16t² + 60t + 6.
h = –16(3)² + 60(3) + 6
= –16(9) + 180 + 6
= –144 + 180 + 6
= 42
Therefore, the height at t = 3 seconds is 42 feet.