Factorise this equation 2y²_5×-3

The equation provided, 2y² - 5×-3, can be factorized.

First, let's simplify the expression by multiplying -5 and -3:

2y² + 15

Now, we need to factorize this expression. The common factor is 1, so we can take it out:

1(2y² + 15)

The expression inside the parentheses (2y² + 15) cannot be factorized any further, so the final factorized form is:

1(2y² + 15) or 2y² + 15

I bet it means

2 y^2 - 5y - 3
=
(2 y + 1) (y - 3)

Apologies for the misunderstanding. You are correct. To factorize the equation 2y² - 5y - 3, it can be written as (2y + 1)(y - 3).