A box has these letters inside it: B N T P N N T P B B N T. Which answer shows how to find the probability of drawing two Ns if the first letter is replaced before drawing the second?(1 point)
To find the probability of drawing two Ns if the first letter is replaced before drawing the second, we need to determine the number of Ns in the box and the total number of letters in the box.
Counting the number of Ns in the box: B N T P N N T P B B N T
There are a total of 3 Ns in the box.
Counting the total number of letters in the box: B N T P N N T P B B N T
There are a total of 12 letters in the box.
The probability of drawing an N on the first draw is 3/12.
Since the first letter is replaced before drawing the second, the probability of drawing another N on the second draw is also 3/12.
To find the probability of drawing two Ns, we multiply the probabilities of both events together:
(3/12) * (3/12) = 9/144 = 1/16
The answer is 1/16.