Convert the following binary numbers to a decimal number. Show all
steps
a. (5)10
b. (105)10
c. (127)10
d. (128)10
e. (192)10
f. (224)10
g. (255)10
h. (256)10
i. Take your own, at least 4 different decimal number and convert it to �
a. (5)10 = 1*2^2 + 0*2^1 + 1*2^0 = 4 + 0 + 1 = (5)10
b. (105)10 = 1*2^6 + 1*2^4 + 0*2^3 + 1*2^2 + 0*2^1 + 1*2^0 = 64 + 16 + 0 + 4 + 0 + 1 = (85)10
c. (127)10 = 1*2^6 + 1*2^5 + 1*2^4 + 1*2^3 + 1*2^2 + 1*2^1 + 1*2^0 = 64 + 32 + 16 + 8 + 4 + 2 + 1 = (127)10
d. (128)10 = 1*2^7 + 0*2^6 + 0*2^5 + 0*2^4 + 0*2^3 + 0*2^2 + 0*2^1 + 0*2^0 = 128 + 0 + 0 + 0 + 0 + 0 + 0 + 0 = (128)10
e. (192)10 = 1*2^7 + 1*2^6 + 0*2^5 + 0*2^4 + 0*2^3 + 0*2^2 + 0*2^1 + 0*2^0 = 128 + 64 + 0 + 0 + 0 + 0 + 0 + 0 = (192)10
f. (224)10 = 1*2^7 + 1*2^6 + 1*2^5 + 0*2^4 + 0*2^3 + 0*2^2 + 0*2^1 + 0*2^0 = 128 + 64 + 32 + 0 + 0 + 0 + 0 + 0 = (224)10
g. (255)10 = 1*2^7 + 1*2^6 + 1*2^5 + 1*2^4 + 1*2^3 + 1*2^2 + 1*2^1 + 1*2^0 = 128 + 64 + 32 + 16 + 8 + 4 + 2 + 1 = (255)10
h. (256)10 = 1*2^8 + 0*2^7 + 0*2^6 + 0*2^5 + 0*2^4 + 0*2^3 + 0*2^2 + 0*2^1 + 0*2^0 = 256 + 0 + 0 + 0 + 0 + 0 + 0 + 0 + 0 = (256)10
i. It seems like the question is cut off here. Please provide the binary numbers to continue.