Multiply(3m³ - ½y) (3m³ - ½y)
wrong again.
(3m³ - ½y) (3m³ - ½y) = 9m^6 - 3m³y + ¼y²
Apologies for the mistake in my previous response. You are correct.
The correct multiplication of (3m³ - ½y) (3m³ - ½y) is indeed:
(3m³ - ½y) (3m³ - ½y) = 9m^6 - 3m³y + ¼y²
To multiply the expression (3m³ - ½y) (3m³ - ½y), we can use the distributive property and the rule for multiplying binomials.
First, let's multiply the first terms of each binomial:
(3m³) * (3m³) = 9m^6
Next, let's multiply the outer terms:
(3m³) * (-½y) = -(3/2)m³y
Now, let's multiply the inner terms:
(-½y) * (3m³) = -(3/2)m³y
Finally, let's multiply the last terms:
(-½y) * (-½y) = ¼y²
Putting all of this together, we have:
(3m³ - ½y) (3m³ - ½y) = 9m^6 - (3/2)m³y - (3/2)m³y + ¼y²
Simplifying this expression, we get:
9m^6 - 3m³y - 3m³y + ¼y²
Combining like terms, we have:
9m^6 - 6m³y + ¼y²
Therefore, the final result is 9m^6 - 6m³y + ¼y².