Jae bought 85 tickets to spend on games and rides at an amusement park. Games cost 3 tickets each, and rides cost 8 tickets each. Jae has already used 39 of the tickets. If he uses all of his remaining tickets for rides, how many more times can Jae go on rides? Use the drop-down menu to complete the answer. (1 point) Jae can go on
3 games because 39 tickets used on games / 3 tickets per game = <<39/3=13>>13 games
Then 85 total tickets - 39 tickets used = <<85-39=46>>46 tickets remaining
Therefore, Jae can go on a total of 46 tickets remaining / 8 tickets per ride = <<46/8=5.75>>5.75 rides
We can't have a fraction of a ride, so Jae can go on a total of 5 rides. Answer: \boxed{5}.