A box has these letters inside it: B N T P N N T P B B N T. Which answer shows how to find the probability of drawing two Ns if the first letter is replaced before drawing the second?(1 point)
A: 4/8 x 4/8
B: 4/12 + 4/12
C: 4/12 x 4/12
D: 3/12 x 2/11
The correct answer is C: 4/12 x 4/12.
To find the probability of drawing two Ns with replacement, we need to find the probability of drawing an N on the first draw and an N on the second draw.
Since there are a total of 12 letters in the box, and 4 of them are Ns, the probability of drawing an N on the first draw is 4/12.
After replacing the first letter, there are still 12 letters in the box, but now there are only 3 Ns left. Therefore, the probability of drawing an N on the second draw is 3/12.
To find the probability of both events happening, we multiply the probabilities together: (4/12) x (3/12) = 12/144 = 1/12.
So, the correct answer is C: 4/12 x 4/12.