Find the image vertices for a dilation with center (0, 0) and a scale factor of 4.
Scale Factor = 4
Vertices given in the graph:
A= (-3, 1); B = (4, -3); C = (2, 3) ; D = (-1, 4)
Scale factor = Dimension of the new shape ÷ Dimension of the original shape.
Find the image vertices for a dilation with center (0, 0) and a scale factor of 4.
To find the image vertices for a dilation with a scale factor of 4 and a center at (0, 0), you can multiply the coordinates of the original vertices by the scale factor.
For vertex A = (-3, 1):
x-coordinate of the image = -3 * 4 = -12
y-coordinate of the image = 1 * 4 = 4
So the image vertex of A is (-12, 4).
For vertex B = (4, -3):
x-coordinate of the image = 4 * 4 = 16
y-coordinate of the image = -3 * 4 = -12
So the image vertex of B is (16, -12).
For vertex C = (2, 3):
x-coordinate of the image = 2 * 4 = 8
y-coordinate of the image = 3 * 4 = 12
So the image vertex of C is (8, 12).
For vertex D = (-1, 4):
x-coordinate of the image = -1 * 4 = -4
y-coordinate of the image = 4 * 4 = 16
So the image vertex of D is (-4, 16).
Therefore, the image vertices after the dilation are:
A' = (-12, 4)
B' = (16, -12)
C' = (8, 12)
D' = (-4, 16)