The volume of 6.77 mole of hydrogen gas is
In stoichiometry
To calculate the volume of 6.77 moles of hydrogen gas, we need to use the ideal gas law equation:
PV = nRT
where:
P = pressure (in atm)
V = volume (in liters)
n = number of moles
R = ideal gas constant (0.0821 L.atm/mol.K)
T = temperature (in Kelvin)
First, we need to know the pressure and temperature of the hydrogen gas. Let's assume that the pressure is at standard conditions (1 atm) and the temperature is at room temperature (298 K).
Substituting these values into the equation:
(1 atm)(V) = (6.77 mol)(0.0821 L.atm/mol.K)(298 K)
Simplifying:
V = (6.77 mol)(0.0821 L.atm/mol.K)(298 K) / 1 atm
V = 163.295 L
Therefore, the volume of 6.77 moles of hydrogen gas is approximately 163.295 liters.