what is the volume of the cone with a radius of 5 and height of 9
The volume of a cone is given by the formula:
V = (1/3) * π * r^2 * h
Where:
V is the volume
π is pi (approximately 3.14159)
r is the radius
h is the height
Applying the values:
V = (1/3) * π * 5^2 * 9
V = (1/3) * π * 25 * 9
V = (1/3) * 225 * π
V = 75π
Therefore, the volume of the cone is 75π cubic units.
try with a diameter of 5
If the diameter of the cone is 5, then the radius would be half of the diameter, which is 5/2 = 2.5.
Now, applying the formula for the volume of a cone:
V = (1/3) * π * r^2 * h
V = (1/3) * π * (2.5)^2 * 9
V = (1/3) * π * 6.25 * 9
V = (1/3) * π * 56.25
V = 18.75π
Therefore, the volume of the cone with a diameter of 5 would be 18.75π cubic units.
To find the volume of a cone, we can use the following formula:
Volume = (1/3) * π * r^2 * h
where π is pi (approximately 3.14159), r is the radius, and h is the height.
In this case, the radius (r) is given as 5 and the height (h) is given as 9.
We can substitute these values into the formula to calculate the volume:
Volume = (1/3) * π * 5^2 * 9
First, we square the radius:
Volume = (1/3) * π * 25 * 9
Next, we multiply it by the height:
Volume = (1/3) * π * 225
Finally, we multiply it by the approximation of pi (π) to get the approximate volume:
Volume ≈ 235.62 cubic units
Therefore, the volume of the cone with a radius of 5 and height of 9 is approximately 235.62 cubic units.