What mass of potassium chloride would be formed when 7.5moles of potassium carbonate iv is used.
2Kclo3➡2kcl + 3o2
To find the mass of potassium chloride formed, we need to use the mole ratio between potassium carbonate and potassium chloride from the balanced chemical equation:
2 KClO3 → 2 KCl + 3 O2
From the equation, we can see that 2 moles of KClO3 will give us 2 moles of KCl.
1 mole of KClO3 → 1 mole of KCl
Therefore, the mole ratio between KClO3 and KCl is 1:1.
Given: 7.5 moles of KClO3
According to the mole ratio, the mass of KCl formed will also be 7.5 moles.
So, the mass of KCl formed will be the same as the mass of KClO3 used, which is 7.5 moles.
Molar mass of KClO3:
K (39.10 g/mol) + Cl (35.45 g/mol) + 3 O (16.00 g/mol × 3) = 122.55 g/mol
To find the mass of KCl, multiply the number of moles by the molar mass:
Mass of KCl = 7.5 moles × 122.55 g/mol = 918.56 g
Therefore, 918.56 grams of potassium chloride will be formed when 7.5 moles of potassium carbonate IV is used.