algebra2

evaluate h(-2/3) if h(x) = [[x-2]]

(-2/3)-2 = -2.666666667

is this the right correct?

If those are absolute value signs surrounding the x-2 on the right, then the answer is +2.666..= 8/3

why is it a positive 8/3 instead of a negative because you subtracted 2 from negative 2/3

As I said earlier, it looks like you might have absolute value signs (| |)around the
-8/3. That would make the final answer positive. If those are just brackets [ ] (which would serve no mathematical purpose here) then the answer would be -8/3.

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