A particle starts from rest and moves with a constant acceleration of 0.5m/s2.calculate the time taken by the particle to cover a distance 25m
To solve this problem, we can use the second equation of motion:
s = ut + (1/2)at^2
Where:
s = distance traveled (25m)
u = initial velocity (0m/s)
a = acceleration (0.5m/s^2)
t = time
Since the particle starts from rest, the initial velocity is 0m/s. Therefore, the equation reduces to:
s = (1/2)at^2
25 = (1/2)(0.5)(t^2)
Simplifying further:
25 = 0.25t^2
Dividing both sides of the equation by 0.25:
100 = t^2
Taking the square root of both sides:
t = √100
The square root of 100 is 10. Therefore, the time taken by the particle to cover a distance of 25m is 10 seconds.