Last Sunday, the average temperature was
\[8\%\] higher than the average temperature two Sundays ago. The average temperature two Sundays ago was
\[T\] degrees Celsius.
Which of the following expressions could represent the average temperature last Sunday?
Choose 2 answers:
Choose 2 answers:
(Choice A)
\[1.08T\]
A
\[1.08T\]
(Choice B)
\[\left(1+\dfrac{8}{100}\right)T\]
B
\[\left(1+\dfrac{8}{100}\right)T\]
(Choice C)
\[T+0.08\]
C
\[T+0.08\]
(Choice D)
\[1.8T\]
D
\[1.8T\]
(Choice E)
\[T+8\]
E
\[T+8\]
To find the average temperature last Sunday, we need to add 8% of the average temperature two Sundays ago to the average temperature two Sundays ago.
Choice A is incorrect because it represents the average temperature as 108% of the original temperature, which is too high.
Choice B is correct because it represents the average temperature as the original temperature plus 8% of the original temperature.
Choice C is incorrect because it represents the average temperature as the original temperature plus 0.08, which is not the correct way to calculate a percentage increase.
Choice D is incorrect because it represents the average temperature as 180% of the original temperature, which is too high.
Choice E is incorrect because it represents the average temperature as the original temperature plus 8, which is not the correct way to calculate a percentage increase.
Therefore, the correct choices are \[\left(1+\frac{8}{100}\right)T\] and \[T+0.08\] which are choices B and C.
one answer was wrong
Apologies for the mistake. Let's re-evaluate the choices.
Choice A is still incorrect because it represents the average temperature as 108% of the original temperature, which is too high.
Choice B is correct because it represents the average temperature as the original temperature plus 8% of the original temperature.
Choice C is still incorrect because it represents the average temperature as the original temperature plus 0.08, which is not the correct way to calculate a percentage increase.
Choice D is incorrect because it represents the average temperature as 180% of the original temperature, which is too high.
Choice E is incorrect because it represents the average temperature as the original temperature plus 8, which is not the correct way to calculate a percentage increase.
Therefore, the correct choices are \[\left(1+\frac{8}{100}\right)T\] which is choice B.
To solve this question, you need to understand the given information.
The average temperature last Sunday was 8% higher than the average temperature two Sundays ago. In mathematical terms, this can be represented as:
Average temperature last Sunday = Average temperature two Sundays ago + (8% of Average temperature two Sundays ago)
Now let's analyze each option:
A) 1.08T
This option represents the average temperature as 108% of the average temperature two Sundays ago. Since 8% represents 0.08 as a decimal, this option is correct.
B) \(\left(1+\dfrac{8}{100}\right)T\)
This option also represents the average temperature as 108% of the average temperature two Sundays ago. It is equivalent to option A, just written in a different format. Therefore, this option is also correct.
C) T + 0.08
This option represents the average temperature by adding 0.08 to the average temperature two Sundays ago. Although 0.08 represents 8% as a decimal, it does not account for the "higher than" condition mentioned in the question. Therefore, this option is not correct.
D) 1.8T
This option represents the average temperature as 180% of the average temperature two Sundays ago. Since the question states that the temperature is 8% higher, this option is not correct.
E) T + 8
This option represents the average temperature by adding 8 degrees Celsius to the average temperature two Sundays ago. However, the question mentions the increase in percentage, not a fixed temperature increase. Therefore, this option is not correct.
In conclusion, options A) and B) are the correct expressions that represent the average temperature last Sunday.