26. How many grams of NaOH are required to prepare 350cm3 of 1.25M NaOH
solution?
To find the number of grams of NaOH required, we can use the formula:
grams = (volume (in liters) * molarity * molar mass).
First, we need to convert the volume of the solution in cm3 to liters:
350 cm3 = 350/1000 = 0.35 liters.
Next, we can substitute the given values into the formula:
grams = (0.35 liters * 1.25 mol/l * 40 g/mol) = 0.35 * 1.25 * 40 = 17.5 grams.
Therefore, 17.5 grams of NaOH are required to prepare 350 cm3 of 1.25M NaOH solution.