Methane, ethyne, and hydrogen form the following equilibrium mixture:
2 CH4(g) ⇌ C2H2(g) + 3 H2(g)
While studying this reaction mixture, a chemist analyzed a 4.0 L sealed flask.
The chemist found 0.46 mol of CH4(g), 0.64 mol of C2H2(g), and 0.92 mol of H2(g).
What is the value of Kc for the reaction?
(Show all steps, work, units and a concise final answer)
To find the value of Kc for the reaction, we use the equation:
Kc = ([C2H2] * [H2]^3) / [CH4]^2
First, we need to convert the moles of each substance into their respective concentrations in units of M (molarity).
For CH4:
[CH4] = 0.46 mol / 4.0 L = 0.115 M
For C2H2:
[C2H2] = 0.64 mol / 4.0 L = 0.16 M
For H2:
[H2] = 0.92 mol / 4.0 L = 0.23 M
Now, substitute these values into the equation for Kc:
Kc = (0.16 * (0.23)^3) / (0.115^2)
= (0.16 * 0.012167) / (0.013225)
= 0.001946 / 0.013225
= 0.147
Therefore, the value of Kc for the reaction is 0.147.