In the synthesis of ammonia, the following occurs:
N2 (g) + 3 H2 (g) 2 NH3 (g)
Given the equilibrium concentrations for each gas at 200°C, what is Keq?
[N2] =0.385 M, [H2] =0.75 M, and [NH3] =0.325 M
a. 0.65
b. 0.650
c. 0.888
d. 1.1
e. 1.54
The equilibrium constant (Keq) is calculated by taking the product of the concentrations of the products and raising each concentration to the power of its coefficient in the balanced equation, and then dividing by the product of the concentrations of the reactants raised to the power of their coefficients.
The balanced equation is: N2 (g) + 3 H2 (g) → 2 NH3 (g)
Plugging in the given concentrations, we get:
Keq = ([NH3]^2)/([N2]*[H2]^3)
= (0.325^2)/(0.385*0.75^3)
= 0.650/0.407
= 1.594
Rounding to the appropriate number of significant figures, the answer is 1.59
Therefore, the correct answer is not listed.
what is the correct answer?
the options are
a. 0.65
b. 0.650
c. 0.888
d. 1.1
e. 1.54