The pH of a solution at 25°C in which [OH-]= 3.4 x 10-5 M is
To find the pH of a solution, we can use the equation:
pOH = -log[OH-]
Here, we are given [OH-] = 3.4 x 10^-5 M. Plugging this value into the equation, we find:
pOH = -log(3.4 x 10^-5)
= -(-4.47)
= 4.47
The next step is to find the pH using the relationship:
pH + pOH = 14
Plugging in the value of pOH, we find:
pH + 4.47 = 14
Subtracting 4.47 from both sides, we get:
pH = 14 - 4.47
= 9.53
Therefore, the pH of the solution is 9.53.