What mass of solute is contained in 256 mL of a 0.895 M ammonium chloride solution?
Group of answer choices
12.3 g
53.5 g
47.9 g
13.7 g
none of these
To find the mass of the solute, we need to calculate the number of moles of ammonium chloride in the 256 mL solution, and then multiply it by the molar mass of ammonium chloride.
To calculate the number of moles of ammonium chloride, we can use the formula:
moles = concentration (in M) × volume (in liters)
First, we need to convert the volume of the solution from mL to L:
256 mL = 256/1000 L = 0.256 L
Next, we can plug the values into the formula:
moles = 0.895 M × 0.256 L = 0.22928 moles
Finally, we can multiply the number of moles by the molar mass of ammonium chloride to find the mass:
mass = moles × molar mass
The molar mass of ammonium chloride (NH4Cl) is:
(1 × 14.01 g/mol for N) + (4 × 1.01 g/mol for H) + (1 × 35.45 g/mol for Cl) = 53.49 g/mol
mass = 0.22928 moles × 53.49 g/mol
mass ≈ 12.27 g
Therefore, the mass of solute contained in 256 mL of a 0.895 M ammonium chloride solution is approximately 12.3 g.
So the correct answer is 12.3 g.