Calculate the concentration of chloride ions when 100.0 mL of 0.200 M sodium chloride is mixed with 250.0 mL of 0.150 M calcium chloride.
Group of answer choices
0.095 M
0.350 M
0.271 M
0.164 M
none of these
To calculate the concentration of chloride ions, we need to first calculate the moles of chloride ions present in each solution.
For the sodium chloride solution:
Moles of chloride ions = 0.200 M x 0.100 L = 0.020 mol
For the calcium chloride solution:
Moles of chloride ions = 0.150 M x 0.250 L = 0.0375 mol
Now, we can calculate the total moles of chloride ions by adding the moles from each solution:
Total moles of chloride ions = 0.020 mol + 0.0375 mol = 0.0575 mol
Finally, we can calculate the concentration of chloride ions in the final solution by dividing the total moles by the total volume:
Concentration of chloride ions = 0.0575 mol / (100.0 mL + 250.0 mL) = 0.0575 mol / 0.350 L ≈ 0.164 M
Therefore, the concentration of chloride ions when 100.0 mL of 0.200 M sodium chloride is mixed with 250.0 mL of 0.150 M calcium chloride is approximately 0.164 M. The answer is 0.164 M.