A bird is flying at an average altitude of 10 meters above the ground. After 3 seconds, it settles on a branch that is 3 meters above the ground. Interpret the quotient to describe the rate of change in the bird’s altitude. Give your answer to the nearest hundredth and remember that the bird is descending.(1 point)
The quotient that best represents the rate of change in the bird’s altitude is ?
meters/second.
To find the rate of change in the bird's altitude, we can calculate the difference in altitude divided by the difference in time.
The difference in altitude is 10 meters (starting altitude) - 3 meters (final altitude) = 7 meters.
The difference in time is 3 seconds.
The quotient to describe the rate of change in the bird's altitude is 7 meters / 3 seconds.
To express this answer to the nearest hundredth, we divide 7 by 3 and round the result to two decimal places:
7 / 3 = 2.333
Therefore, the quotient that best represents the rate of change in the bird's altitude is approximately 2.33 meters/second.
are you sure because that doesnt work fo me
Apologies for the confusion. It seems like I made a mistake in the calculation. Let's recalculate the rate of change in the bird's altitude.
The difference in altitude is 10 meters (starting altitude) - 3 meters (final altitude) = 7 meters.
The difference in time is 3 seconds.
To find the rate of change, we divide the difference in altitude by the difference in time:
7 meters / 3 seconds = 2.33 meters per second.
So, the quotient that best represents the rate of change in the bird's altitude is approximately 2.33 meters/second.
negative?
Apologies for the oversight. Since the bird is descending, the rate of change should be negative. Let's recalculate the rate of change in the bird's altitude, taking into account the negative direction.
The difference in altitude is 3 meters (final altitude) - 10 meters (starting altitude) = -7 meters.
The difference in time is 3 seconds.
To find the rate of change, we divide the difference in altitude by the difference in time:
-7 meters / 3 seconds = -2.33 meters per second.
So, the correct quotient that best represents the rate of change in the bird's altitude is approximately -2.33 meters/second.
To find the rate of change in the bird's altitude, we need to calculate the change in altitude over the change in time.
The initial altitude is 10 meters, and after 3 seconds, it settles at an altitude of 3 meters.
To find the change in altitude, we subtract the initial altitude from the final altitude:
Change in altitude = Final Altitude - Initial Altitude
Change in altitude = 3 meters - 10 meters
Change in altitude = -7 meters
The change in time is given as 3 seconds.
Now we can calculate the rate of change, which is the change in altitude divided by the change in time:
Rate of change = Change in altitude / Change in time
Rate of change = -7 meters / 3 seconds
To get the answer to the nearest hundredth, we can divide -7 by 3 and round to two decimal places:
Rate of change = -7 / 3 ≈ -2.33 meters/second
Therefore, the quotient that best represents the rate of change in the bird's altitude is approximately -2.33 meters/second.