Tomaz draws a circle and dilates it on a photocopier using a scale factor of 3. If the original circle has a radius of 3 cm, what is the area of the dilated circle? Round your answer to the nearest tenth of a square centimeter.
The diameter of the original circle is 2*3 = <<2*3=6>>6 cm
The radius of the dilated circle is 3*3 = <<3*3=9>>9 cm
The area of the dilated circle is pi*9^2 = 254.46900494 square cm
Rounded to the nearest tenth of a square centimeter, the area of the dilated circle is 254.5 square cm. Answer: \boxed{254.5}.