x y
4 1
8 2
12 3
16 4
Compare the table of Object A and the equation y = 15
x of Object B. Which of the two moving objects has greater speed and by what factor? (round to nearest hundredth)
Responses
A Object A by a factor of 1.05Object A by a factor of 1.05
B Object B by a factor of 1.05Object B by a factor of 1.05
C Object A by a factor of 1.25Object A by a factor of 1.25
D Object B by a factor of 1.25
To compare the speed of the two objects, we need to calculate the average speed for both objects. Average speed is equal to the change in distance divided by the change in time.
For Object A:
Change in distance = 4 meters (16 - 4 = 12)
Change in time = 3 seconds (4 - 1 = 3)
Average speed of Object A = Change in distance / Change in time = 4/3 = 1.33 meters per second
For Object B:
Change in distance = 15 meters (15 - 0 = 15)
Change in time = 4 seconds (8 - 4 = 4)
Average speed of Object B = Change in distance / Change in time = 15/4 = 3.75 meters per second
Since the average speed of Object B (3.75 m/s) is greater than the average speed of Object A (1.33 m/s), we can conclude that Object B has a greater speed.
To find the factor by which Object B's speed is greater, we divide the average speed of Object B by the average speed of Object A.
Factor = Average speed of Object B / Average speed of Object A = 3.75 / 1.33 ≈ 2.82
Rounded to the nearest hundredth, the factor is approximately 2.82.
Therefore, the correct answer is:
D) Object B by a factor of 2.82