The length of a rectangle is 2 yd longer than its width. If the perimeter of the triangle is 52 yd, find its length and width.
Let x be the width of the rectangle.
The length of the rectangle is x+2.
The perimeter of the rectangle is 2*x + 2*(x+2)=52.
Simplifying the expression, we get 2x + 2x + 4 = 52.
Combining like terms, we get 4x + 4 = 52.
Subtracting 4 from both sides, we get 4x = 48.
Dividing both sides by 4, we get x = 12.
Thus, the width of the rectangle is 12 yards and the length is 12+2 = <<12+2=14>>14 yards. Answer: \boxed{12, 14}.