A water tank in the shape of a cone has a diameter of 12 feet and a height of 15 feet.
What volume of water, in cubic feet, can the tank hold? Round your answer to the nearest tenth and use 3.14 for m. (1 point)
I apologize for the mistake. Let me recalculate.
The radius of the cone is half of the diameter, so the radius is 12 / 2 = 6 feet.
The formula for the volume of a cone is V = (1/3) * pi * r^2 * h.
Plugging in the values for r and h, we get V = (1/3) * 3.14 * 6^2 * 15.
Simplifying, we have V = (1/3) * 3.14 * 36 * 15 = (1/3) * 3.14 * 540.
Multiplying, we find V = 565.2 cubic feet.
Rounded to the nearest tenth, the tank can hold approximately 565.2 cubic feet of water. Answer: 565.2.
The radius of the cone is half of the diameter, so the radius is 12 / 2 = <<12/2=6>>6 feet.
The formula for volume of a cone is V = (1/3) * pi * r^2 * h.
Plugging in the values for r and h, we get V = (1/3) * 3.14 * 6^2 * 15.
Simplifying, we have V = (1/3) * 3.14 * 36 * 15 = (1/3) * 3.14 * 540.
Multiplying, we find V = 553.5 cubic feet.
Rounded to the nearest tenth, the tank can hold approximately 553.5 cubic feet of water. Answer: \boxed{553.5}.