Which of the following equations has a solution of -8?
Options:
x - 10 = 2
x - 4 = 12
x + 3 = -11
x - 8 = 0
To find which equation has a solution of -8, we can substitute -8 for $x$ in each equation and see which equation is satisfied.
1) $x - 10 = 2$. Substituting $x = -8$, we have $-8 - 10 = 2$, which is not true.
2) $x - 4 = 12$. Substituting $x = -8$, we have $-8 - 4 = 12$, which is not true.
3) $x + 3 = -11$. Substituting $x = -8$, we have $-8 + 3 = -11$, which is true.
4) $x - 8 = 0$. Substituting $x = -8$, we have $-8 - 8 = 0$, which is not true.
Therefore, the equation that has a solution of $-8$ is $\boxed{x + 3 = -11}$.