The sequence A_n is such that an = 2a_n – 1 + 1. If a_6 = 191 and a_5 = 95, what is the
value of a_2?
We can rewrite the equation an = 2a_n – 1 + 1 as aₙ = 2aₙ₋₁ - 1 + 1 = 2aₙ₋₁, which means that each term is twice the previous term.
Using this pattern, we can find a₂ by repeatedly doubling a₅:
a₅ = 95
a₄ = 2 * a₅ = 2 * 95 = 190
a₃ = 2 * a₄ = 2 * 190 = 380
a₂ = 2 * a₃ = 2 * 380 = <<2*380=760>>760
Therefore, the value of a₂ is 760.