what is the quadratic eqaution that has the roots 3+i and 3-i
x^2+6x-10=0
x^2-6x+8=0
x^2-6x+10=0
x^2+6x+10=0
The quadratic equation that has the roots 3+i and 3-i is:
(x - (3+i))(x - (3-i)) = 0
By simplifying this equation, we get:
(x - 3 - i)(x - 3 + i) = 0
(x - 3)^2 - (i)^2 = 0
(x - 3)^2 - (-1) = 0
(x - 3)^2 + 1 = 0
Expanding the equation, we get:
x^2 - 6x + 9 + 1 = 0
x^2 - 6x + 10 = 0
Therefore, the correct answer is x^2 - 6x + 10 = 0.