Consider the following quadratic equation:
6x^2=31x−5
Step 1 of 2 : Using the standard form ax2+bx+c=0
of the given quadratic equation, factor the left hand side of the equation into two linear factors.
To factor the left hand side of the equation into two linear factors, we write the equation in standard form:
6x^2 - 31x + 5 = 0
We need to find two numbers that multiply to give 5 * 6 = 30 and add to give -31.
The numbers that satisfy these conditions are -30 and -1.
So, we can write the equation as:
(2x - 1)(3x - 5) = 0
Thus, the left hand side of the equation is factored into two linear factors, (2x - 1) and (3x - 5).