One object is traveling northeast with a momentum of 12 kg-m/s, while a second object is traveling southwest on the same path as the first object with a momentum of 4 kg-m/s. When the two objects collide, they stick together. What is the momentum after their collision?(1 point) Responses 8 kg-m/s southwest 8 kg-m/s southwest 16 kg-m/s northeast 16 kg-m/s northeast 8 kg-m/s northeast 8 kg-m/s northeast 16 kg-m/s southwest
To solve this problem, we need to add the momentum vectors of the two objects before collision to find the combined momentum after the collision.
The first object has a momentum of 12 kg-m/s, moving northeast. We can represent this momentum as a vector with magnitude 12, pointing in the northeast direction.
The second object has a momentum of 4 kg-m/s, moving southwest. We can represent this momentum as a vector with magnitude 4, pointing in the southwest direction.
To find the combined momentum after the collision, we add these two momentum vectors together. Since they are on the same path, we can simply add their magnitudes and choose the direction based on the larger momentum.
12 kg-m/s + 4 kg-m/s = 16 kg-m/s
The momentum after the collision is 16 kg-m/s. Since the larger momentum is from the northeast direction, the answer is 16 kg-m/s northeast. Therefore, the correct response is:
16 kg-m/s northeast
is this right
Yes, that is correct. The combined momentum after the collision is 16 kg-m/s, and it is in the northeast direction.
To find the momentum after the collision, we need to consider the principle of conservation of momentum. According to this principle, the total momentum before the collision should be equal to the total momentum after the collision.
In this case, the first object has a momentum of 12 kg-m/s northeast (positive direction) and the second object has a momentum of 4 kg-m/s southwest (negative direction). To make calculations easier, we can assign the northeast direction as positive (+) and the southwest direction as negative (-).
So, the total momentum before the collision would be: 12 kg-m/s + (-4 kg-m/s) = 8 kg-m/s northeast.
After the collision, the two objects stick together and move as one. We need to find the momentum of the combined object.
Since momentum is a vector quantity, we can denote the momentum of the combined object as (+) or (-) based on the direction it moves after the collision.
Since the objects were moving in opposite directions (northeast and southwest) before the collision, the momentum of the combined object will be in the direction of the larger momentum (northeast).
Therefore, the momentum after the collision would be 8 kg-m/s northeast. So the correct response is 8 kg-m/s northeast.