The product of two consecutive even integers is 168 find the integers
Let's call the two consecutive even integers x and x+2.
According to the problem, the product of these two numbers is 168. So we can write the equation:
x(x+2) = 168
Expanding the equation and rearranging terms, we get:
x^2 + 2x = 168
To solve this quadratic equation, we need to set it equal to zero:
x^2 + 2x - 168 = 0
Now we can either factor this equation or use the quadratic formula. Let's factor it:
(x - 12)(x + 14) = 0
Setting each factor equal to zero, we get two solutions:
x - 12 = 0 --> x = 12
x + 14 = 0 --> x = -14
Since we're looking for even integers, we can discard the second solution (-14). Therefore, the two consecutive even integers are 12 and 14.