Xavier is installing two sections of pipe. The first section is 5.7 m long and makes an angle of 25" below the horizontal. The second section of pipe is attached at the end of the first, with a bend. The second pipe is 5.3 m long and makes an angle of 37° below the horizontal. What is the total drop from the start of the first pipe to the end of the second pipe?
4.5 m
04.3 m
5.6 m
7 m
To solve this problem, we can break it down into two parts:
First, let's find the vertical component of the first pipe. We can use trigonometry to find this. The vertical component is given by:
Vertical component = Length of the pipe * sin(angle)
For the first pipe, the vertical component is:
Vertical component of the first pipe = 5.7 * sin(25°) = 2.498 m
Next, let's find the vertical component of the second pipe. We can use the same formula again:
Vertical component of the second pipe = 5.3 * sin(37°) = 3.188 m
Now, let's find the total drop from the start of the first pipe to the end of the second pipe. We can simply add the vertical components of both pipes:
Total drop = Vertical component of the first pipe + Vertical component of the second pipe
= 2.498 m + 3.188 m
= 5.686 m
Rounding this value to the nearest tenth gives us 5.7 m.
Therefore, the total drop from the start of the first pipe to the end of the second pipe is 5.7 m.