Using the graph, determin the equation of the line is slope-intercept form
Two points on the line are (1,-12) and (5,15)
To find the equation of the line in slope-intercept form, we need to find the slope and the y-intercept.
First, let's find the slope (m) using the formula:
m = (y2 - y1) / (x2 - x1)
Using the points (1, -12) and (5, 15):
m = (15 - (-12)) / (5 - 1)
m = (15 + 12) / 4
m = 27 / 4
Now that we have the slope, we can use the point-slope form of a linear equation to find the equation of the line:
y - y1 = m(x - x1)
Using the point (1, -12) and the slope 27/4:
y - (-12) = (27/4)(x - 1)
y + 12 = (27/4)(x - 1)
To convert it into slope-intercept form (y = mx + b), we need to isolate y:
y + 12 = (27/4)x - 27/4
y = (27/4)x - 27/4 - 48/4
y = (27/4)x - 75/4
Hence, the equation of the line in slope-intercept form is y = (27/4)x - 75/4.