Net Force and Acceleration Quick Check 5 of 55 of 5 Items Question Two teams are playing tug of war. The tables show the members of each team and how much pulling force each team member applies to the rope. Team A Members Pulling Force (N) Darlene 360 Eric 400 Keshawn 450 Team B Members Pulling Force (N) Anita 350 Frank 390 Molly 490 If Team A pulls to the right and Team B pulls to the left, what is the total horizontal net force applied to the rope? (1 point) Responses 40 N to the right 40 N to the right 20 N to the left 20 N to the left 40 N to the left 40 N to the left 20 N to the right 20 N to the right
To find the total horizontal net force, you need to subtract the sum of Team A's pulling forces from the sum of Team B's pulling forces.
Sum of Team A's pulling forces: 360 + 400 + 450 = 1210 N
Sum of Team B's pulling forces: 350 + 390 + 490 = 1230 N
Total horizontal net force = Sum of Team B's pulling forces - Sum of Team A's pulling forces
= 1230 N - 1210 N
= 20 N to the right
Therefore, the total horizontal net force applied to the rope is 20 N to the right.
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To find the total horizontal net force applied to the rope, we need to find the vector sum of the individual forces applied by each team member.
For Team A, the individual forces are 360 N, 400 N, and 450 N, all pulling to the right. Adding these forces gives us:
360 N + 400 N + 450 N = 1210 N to the right
For Team B, the individual forces are 350 N, 390 N, and 490 N, all pulling to the left. Adding these forces gives us:
350 N + 390 N + 490 N = 1230 N to the left
To find the net force, we subtract the total force applied by Team B from the total force applied by Team A:
1210 N - 1230 N = -20 N
The negative sign indicates the direction of the net force, which is to the left.
Therefore, the total horizontal net force applied to the rope is 20 N to the left.