Sasha is at a Bearcat hockey game. She sees her best friend seated 5 meters ahead of her and then her volleyball teammate seated 7 meters to her left. How far apart are her best friend and teammate?
Hint: draw a picture and use the formula a2+b2=c2
A.
3.5 m
B.
12 m
C.
8.6 m
To find the distance between Sasha's best friend and her volleyball teammate, we can use the Pythagorean theorem.
Let's denote Sasha as point S, her best friend as point F, and her volleyball teammate as point T.
We can create a right triangle using SF and ST as two sides. The distance between Sasha's best friend and her teammate will be the length of the hypotenuse.
We know that SF is 5 meters and ST is 7 meters.
Using the Pythagorean theorem (a^2 + b^2 = c^2), we can find the length of the hypotenuse:
SF^2 + ST^2 = c^2
5^2 + 7^2 = c^2
25 + 49 = c^2
74 = c^2
Taking the square root of both sides:
c ≈ √74
c ≈ 8.6
Therefore, the distance between Sasha's best friend and volleyball teammate is approximately 8.6 meters.
So the answer is C. 8.6 m.