The numbers 4725 and 126, written as the products of their prime factors, are 4725=3 power of 3x 5 squared x 7and 126 = 2 x 3squared x 7
The largest integer which is a factor of 4725 and 126.
To find the largest integer which is a factor of both 4725 and 126, we need to find the common prime factors of these numbers.
The prime factorization of 4725 is 3^3 * 5^2 * 7.
The prime factorization of 126 is 2 * 3^2 * 7.
The common prime factors are 3^2 * 7, which is equal to 63.
Therefore, the largest integer which is a factor of both 4725 and 126 is 63.