Write the point-slope form of the line that passes through (-8, 2) and is perpendicular to a line with a slope of -8. Include all of your work in your final answer. Type your answer in the box provided to submit your solution.
The point-slope form of a linear equation is given by y - y₁ = m(x - x₁), where (x₁, y₁) is a point on the line and m is the slope of the line.
We are given the point (-8, 2) and the slope of the line perpendicular to the given line is -8.
The slope of the line perpendicular to a given line is the negative reciprocal of the slope of the given line.
So, the slope of the perpendicular line is 1/8.
Using the point-slope form, we have y - 2 = 1/8(x - (-8)).
Simplifying, we get y - 2 = 1/8(x + 8).
Therefore, the point-slope form of the line that passes through (-8, 2) and is perpendicular to a line with a slope of -8 is y - 2 = 1/8(x + 8).