Molarity of CH3CO2H when there are 0.0019536 moles of CH3CO2H and the volume of NaOH tires red was 16.28 mL
To determine the molarity of CH3CO2H, we need to use the equation:
Molarity (M) = moles of solute / volume of solution in liters
Given:
moles of CH3CO2H = 0.0019536 moles
volume of NaOH titrated = 16.28 mL = 0.01628 L
Now, substitute the values into the equation:
Molarity (M) = 0.0019536 moles / 0.01628 L
Calculating this gives:
Molarity (M) ≈ 0.120 M
Therefore, the molarity of CH3CO2H is approximately 0.120 M.