Please solve the inequality
.04 x + .06(12000-x) >= 650
.04x + 720 - .06x ≥ 650
-.02x ≥ -70
x ≥ -70/-.02
x ≥ 3500
Shouldn't the answer be less than or = to?
yes, of course you are right.
When dividing by a negative we have to reverse the inequality sign.
Time for my third cup of coffee.
To solve the given inequality, let's simplify it step by step:
First, distribute the 0.06:
0.04x + 0.06(12000) - 0.06x >= 650
Now simplify:
0.04x + 720 - 0.06x >= 650
Combine like terms:
0.04x - 0.06x + 720 >= 650
-0.02x + 720 >= 650
Next, isolate the x variable by subtracting 720 from both sides:
-0.02x + 720 - 720 >= 650 - 720
-0.02x >= -70
Now, divide both sides of the inequality by -0.02 (remember to flip the inequality sign when dividing by a negative number):
(-0.02x)/(-0.02) <= -70 / (-0.02)
x <= 3500
So, the solution to the inequality is x <= 3500.