What is the molarity of dilute NaOH made from an original molarity of concentrated NaOH of 6.0 M, a volume of concentrated NaOH of 5.0 mL, and the final volume of diluted NaOH of 250 mL
To find the molarity of the dilute NaOH, we can use the dilution formula:
M1V1 = M2V2
Where:
M1 = initial molarity of concentrated NaOH = 6.0 M
V1 = initial volume of concentrated NaOH = 5.0 mL = 0.005 L (since 1 mL = 0.001 L)
M2 = final molarity of dilute NaOH (to be determined)
V2 = final volume of diluted NaOH = 250 mL = 0.25 L (since 1 mL = 0.001 L)
Substituting the given values into the formula:
(6.0 M)(0.005 L) = M2(0.25 L)
0.03 mol = 0.25 M2
Now, solve for M2:
M2 = 0.03 mol / 0.25 L
= 0.12 M
Therefore, the molarity of the dilute NaOH is 0.12 M.