Henry has a pot with 6 3/10 liters of water. He pours out 3 1/5 liters of water. How many liters of water remain in the pot
To solve the problem, we need to subtract the amount of water poured out from the initial amount of water.
Initial amount of water = 6 3/10 liters = 63/10 liters.
Amount of water poured out = 3 1/5 liters = 16/5 liters.
Remaining amount of water = Initial amount of water - Amount of water poured out = 63/10 liters - 16/5 liters.
To subtract the fractions, we need to have the same denominator.
Multiplying the numerator and denominator of the 2nd fraction by 2 gives us: 2 * (16/5) = 32/10 liters.
Remaining amount of water = 63/10 liters - 32/10 liters = (63 - 32)/10 liters = 31/10 liters.
Therefore, there are 31/10 liters of water remaining in the pot.