Of the 72 students who have Ms. Darnell for Health/PE, 9 have an A. At this rate, how many of the 16 students in Ms. Jay’s homeroom would you expect to have an A? (1 point)
students
At the same rate, we can expect 9 out of 72 students to have an A in Ms. Darnell's class.
To find out how many students in Ms. Jay's homeroom would be expected to have an A, we can use proportions.
The proportion of students who have an A in Ms. Darnell's class is 9/72.
We can set up a proportion using this information:
9/72 = x/16
To find x, we need to cross-multiply and solve for x:
72x = 9 * 16
72x = 144
x = 144/72
x = 2
Therefore, we would expect 2 out of the 16 students in Ms. Jay's homeroom to have an A.