a sequence can be generated by using a n =3a(n-1) where a1=6 and n is a whole number greater then 1. what are the first four terms of the sequence
To generate the first four terms of the sequence, we can use the given formula.
Let's plug in n = 1 to find the first term of the sequence:
a(1) = 3a(1-1) = 3a(0) = 3a(1-1) = 3a(0) = 3a(0) = 3(6) = 18.
Therefore, the first term of the sequence is 18.
Now let's find the second term by plugging in n = 2:
a(2) = 3a(2-1) = 3a(1) = 3(18) = 54.
The second term of the sequence is 54.
Next, let's find the third term by plugging in n = 3:
a(3) = 3a(3-1) = 3a(2) = 3(54) = 162.
The third term of the sequence is 162.
Finally, let's find the fourth term by plugging in n = 4:
a(4) = 3a(4-1) = 3a(3) = 3(162) = 486.
The fourth term of the sequence is 486.
Therefore, the first four terms of the sequence are: 18, 54, 162, 486.