Find the real solutions of the following equation by graphing.
x^3-9x^2+20x=0
To graph the equation, we need to set it equal to y and create a table of values to plot points.
Setting the equation equal to y:
y = x^3 - 9x^2 + 20x
Creating a table of values:
x | y
0 | 0
1 | 12
2 | 24
3 | 18
4 | 0
Plotting the points on the graph, we get:
y-axis
|
| o
| o
| o
| o
|_____________________
x-axis
Connecting the plotted points, we get:
y-axis
|
| o
| o
| o
|--------o-----o
|_____________________
x-axis
From the graph, we can see that there are two real solutions:
x = 0 and x = 4