4/9 of the pupils in a school are chinese. 1/3 of them are malays. The rest are indians. If there are 428 indians pupils in the school. How many pupils are there in the school together?
Let's represent the total number of pupils in the school as x.
4/9 of the pupils are Chinese, so there are (4/9)*x Chinese pupils.
1/3 of the pupils are Malays, so there are (1/3)*x Malay pupils.
The rest, which are Indians, are represented by 428 pupils.
Therefore, the equation becomes:
(4/9)*x + (1/3)*x + 428 = x
To simplify the equation, we can multiply both sides by 9 to eliminate the denominators:
4x + 3x + 3852 = 9x
Combining like terms, the equation becomes:
7x + 3852 = 9x
Subtracting 7x from both sides gives us:
3852 = 2x
Finally, dividing both sides by 2 gives us the value of x:
x = 1926
Therefore, there are 1926 pupils in the school.