There are three choices of fruit are bananas, pears, and oranges. If the probability of getting a banana is 5/12 and the probability of getting a pear is 1/6, what is the probability of getting an orange?
Responses
A 5/12
B 1/2
C 1/3
D 1/12
Since there are only three choices of fruit and the probabilities of getting a banana and a pear have already been given, we can calculate the probability of getting an orange by subtracting the sum of the probabilities of getting a banana and a pear from 1.
Probability of getting an orange = 1 - (Probability of getting a banana + Probability of getting a pear)
= 1 - (5/12 + 1/6)
= 1 - (10/24 + 4/24)
= 1 - (14/24)
= 1 - 7/12
= 5/12
Therefore, the probability of getting an orange is 5/12.
The correct answer is A) 5/12.