20.0cm of H_{2}*S*O_{4} reacts with 25c * m ^ 3 of 0.200 mol/dm³ NaOH.
The equation for the reaction is shown.
H_{2}*S*O_{1} + 2NaOH -> N*a_{2}*S*O_{4} + 2H_{2}*O
Calculate the concentration of H_{2}*S*O_{4} using the following steps. Calculate the number of moles in 25c * m ^ 2 of 0.2mol / d * m ^ 2 NaOH.
⚫ Determine the number of moles of H_{2}*S*O_{4} that react with the NaOH.
Calculate the concentration of H_{2}*S*O_{4}
To calculate the concentration of H₂SO₄, we need to first determine the number of moles of H₂SO₄ that react with the NaOH.
From the balanced chemical equation, we can see that the stoichiometric ratio between H₂SO₄ and NaOH is 1:2. This means that for every 1 mole of H₂SO₄, 2 moles of NaOH react.
Given that we have 25 cm³ of 0.2 mol/dm³ NaOH, we can calculate the number of moles of NaOH as follows:
Number of moles of NaOH = (Volume in dm³) × (Concentration in mol/dm³)
= (25 cm³) × (0.2 mol/dm³)
= 5 × 10⁻³ mol
Now, since the stoichiometric ratio between H₂SO₄ and NaOH is 1:2, we can determine the number of moles of H₂SO₄ that react with the NaOH as follows:
Number of moles of H₂SO₄ = (Number of moles of NaOH) / 2
= (5 × 10⁻³ mol) / 2
= 2.5 × 10⁻³ mol
Finally, to calculate the concentration of H₂SO₄, we need to divide the number of moles of H₂SO₄ by the volume in dm³:
Concentration of H₂SO₄ = (Number of moles of H₂SO₄) / (Volume in dm³)
= (2.5 × 10⁻³ mol) / (20.0 cm³ / 1000)
= (2.5 × 10⁻³ mol) / 0.02 dm³
= 0.125 mol/dm³
Therefore, the concentration of H₂SO₄ is 0.125 mol/dm³.