A solid weighing 0.40N in air and 0.26N when fully immersed in a liquid of density 800kg/m3. Calculate the volume in solid?
When the solid is immersed in the liquid, it loses weight equal to the weight of the liquid displaced by the solid.
Let V be the volume of the solid.
Therefore, the weight of the liquid displaced by the solid = density of the liquid × volume of the solid × acceleration due to gravity.
Given:
Weight of the solid in air = 0.40 N
Weight of the solid when fully immersed in the liquid = 0.26 N
Density of the liquid = 800 kg/m^3
Weight of the liquid displaced = Weight of the solid in air - Weight of the solid when fully immersed in the liquid
= 0.40 N - 0.26 N
= 0.14 N
Weight of the liquid displaced = density of the liquid × volume of the solid × acceleration due to gravity
Therefore, 0.14 N = 800 kg/m^3 × V × 9.8 m/s^2
Simplifying the equation:
0.14 N = 7840 V
V = 0.14 N / 7840
V ≈ 1.79 × 10^(-5) m^3
Therefore, the volume of the solid is approximately 1.79 × 10^(-5) m^3.