The interior angles of a pentagon are x 2x plus 60 and x substract the 10 find the value of x
The sum of the interior angles of a pentagon is (n-2) * 180, where n is the number of sides of the polygon. Since we have a pentagon, n = 5.
So, the sum of the interior angles is (5-2) * 180 = 3 * 180 = 540 degrees.
According to the given information, the sum of the interior angles is also equal to x + 2x + 60 + x - 10.
Simplifying this equation, we get: x + 2x + x + 60 - 10 = 540.
Combining the like terms, we get: 4x + 50 = 540.
Subtracting 50 from both sides of the equation, we get: 4x = 540 - 50.
Simplifying the right side of the equation, we get: 4x = 490.
Now, dividing both sides of the equation by 4, we get: x = 490/4.
Simplifying the right side of the equation, we get: x = 122.5.
Therefore, the value of x is 122.5.